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: Gain mastery over ratio and proportion problems #IndiaNEWS #Education Today Hyderabad: This article is in continuation to the last article focusing on the ratio and proportion topic. Here are some

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Posted in: #IndiaNEWS #Education

Gain mastery over ratio and proportion problems #IndiaNEWS #Education Today
Hyderabad: This article is in continuation to the last article focusing on the ratio and proportion topic. Here are some practice questions along with solutions on the ratio and proportion topic that will help you in your preparation for the State government recruitment jobs.
1. A person distributes his pens among four friends A, B, C, D in the ratio 1/3:1/4:1/5:1/6. What is the minimum number of pens that the person should have?
a) 55 b) 57 c) 65 d) 67
Ans: b
Solution: 1/3:1/4:1/5:1/6
LCM of 3,4,5,6 is 60
(1/3)×60 : (1/4)×60: (1/5)×60 : (1/6)×60
20 : 15 : 12 : 10
Therefore, minimum number of pens
= 20 15 12 10 = 57
2. If a³ b³ : a³ b³ = 185 : 158 then a : b?
a) 3 : 7 b) 7 : 3 c) 2 : 3 d) 3 : 2
Ans: b
Solution: a³ b³ / a³ b³ = 185/158
By componendo and dividendo
{(a³ b³) (a³ b³)} / {(a³ b³) (a³ b³)} = 185 158 / 185 158
2a³ / 2b³ = 343/27
a³ / b³ = 7³ / 3³
7 : 3
3. The ratio of two weights, 27kg and 108gm is
a) 1 : 250 b) 1 : 270 c) 250 : 1 d) 270 : 1
Ans: c
Solution: 27 × 1000gm / 108gm
= 1000/4
= 250: 1
4. If 3/5 of a bottle is filled, what is the ratio of the filled part to the empty part of the bottle?
a) 3 : 1 b) 3 : 2 c) 1 : 3 d) 3 : 1
Ans: b
Solution: 1 (= Full bottle)
Filled part empty part
3/5 2/5
3/5 : 2/5
3 : 2
5. If A : B = 3 : 4 and B : C = 6 : 5, then A : (A C) = ?
a) 9 : 19 b) 9 : 10 c) 9 : 11 d) 11 : 9
Ans: a
Solution: A : B = 3 : 4
B : C = 6 : 5
A : B : C = 9 : 12 : 10
A : (A C) = 9 : 19
6. What is the compound ratio of 45 : 75, 3 : 5, 51 : 68 and 256 : 81?
a) 64 : 75 b) 128 : 75 c) 32 : 45 d) 75 : 32
Ans: a
Solution: Compound ratio = (45×3×51×256) / (75×5×68×81)
= 64/75
7. A is twice of B, B is half of D, D is three times of C. A is how many times of D?
a) 1 b) 0.5 c) 2 d) 3
Ans: a
Solution: A = 2B >; A : B = 2 : 1
B = D >; B : D = 1 : 2
D = 3C >; D : C = 3 : 1
A : B : D = 2 : 1 : 2
D : C = 3 : 1
A : B : D : C = 6 : 3 : 6 : 2
A : D = 6 : 6
= 1 : 1
A = D
To be continued
M. Venkat
Director
MVK Publications
Dilsukhnagar
7671002120


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